Quiz & test questions Grade 12 Engineering & Design

Grebe Point Lift Station: Wet Well and Force Main Test

A grade 12 quiz on a fictional lift station mixing multiple-choice and computation: wet well volume, fill and pump-down times, cycle time, and force main velocity.

Objectives

  1. Students will calculate the wet well volume between pump start and stop levels.
  2. Students will compute fill time, pump-down time, and total cycle time from inflow and pump rates.
  3. Students will determine force main velocity from flow and pipe diameter and evaluate it against a scouring minimum.

Vocabulary

Lift station
A lift station is a pumping setup that raises wastewater from a low spot so it can keep flowing toward the treatment plant. Sewers mostly flow downhill, so low areas need a lift.

Also: wet well, force main, cycle time, scouring velocity

Teacher overview

This 35-minute quiz, worth 30 points, checks whether students can carry lift-station design math from the wet well through the force main. It mixes two multiple-choice items, five computation items, and one short-answer item, all built on a single fictional station, so answers from early items feed the later ones the way a design check actually proceeds.

Answer Key

  1. Answer: B) Raise wastewater so it can continue flowing by gravity where the ground no longer slopes downhill. Lift stations are installed where the ground stops sloping downhill far enough for gravity flow to continue, while treatment steps such as disinfection and grit removal happen at the plant rather than at the station.
  2. Answer: B) The wet well level rising to the lead pump's start setpoint. Level controls, floats or transducers, cycle the pumps; timers would ignore how much wastewater has actually arrived.
  3. Answer: 2,114 gallons. Volume = 0.785 × 12² × 2.5 = 0.785 × 144 × 2.5 = 282.6 cubic feet, and 282.6 × 7.48 = 2,113.8, about 2,114 gallons.
  4. Answer: 14.1 minutes. 2,113.8 gallons ÷ 150 gpm = 14.09, about 14.1 minutes of filling between cycles.
  5. Answer: 8.5 minutes. The pump gains on the well at 400 − 150 = 250 gpm net, so 2,113.8 ÷ 250 = 8.46, about 8.5 minutes to pump down.
  6. Answer: 4.5 feet per second. 400 gpm ÷ 448.8 gpm per cfs = 0.891 cfs. Pipe area = 0.785 × 0.5² = 0.196 square feet. V = Q ÷ A = 0.891 ÷ 0.196 = 4.54, about 4.5 feet per second.
  7. Answer: 22.6 minutes. Cycle = fill + pump-down = 14.1 + 8.5 = 22.6 minutes, so the lead pump starts about 60 ÷ 22.6 = 2.7 times per hour.
  8. Answer: It keeps solids moving, scouring the pipe. At or above roughly 2 feet per second the flow resuspends grease and grit so they do not settle and build up in the force main. Acceptable design changes: use a smaller-diameter force main so the same flow moves faster, or select a higher-capacity pump; either raises velocity.

Differentiation

Support

Provide the three formulas printed at the top of the quiz with the wet well's 0.785 × 144 product already evaluated, and allow items 4, 5, and 7 to use the rounded 2,114-gallon value without penalty for the small difference it introduces.

Extension

Suppose a storm doubles the fictional station's inflow to 300 gpm. Have students recompute the fill time from item 4 and the net pump-down rate from item 5, then explain which of the two changes threatens the station first as inflow keeps climbing toward the pump's 400 gpm capacity. (Fill time drops to about 7.0 minutes; the net rate collapses to 100 gpm.)

ELL supports

Provide a labeled cutaway sketch of the station showing the wet well, the start and stop levels, the pumps, and the force main climbing the ridge, and let students annotate it during the quiz. Offer a sentence frame for item 8: "The velocity keeps ___ from settling in the pipe, and using a ___ pipe would make the water move faster."