Math problem set Grade 6 Engineering & Design

Northgate School Low-Flow Fixture Retrofit Problems

A grade 6 engineering set where students plan a fixture retrofit, comparing shower and faucet flow rates to find water and cost savings with percent and an equation.

Objectives

  1. Students will compare fixture flow rates to find gallons and percent of water saved.
  2. Students will write and solve a one-step equation to fit a retrofit purchase to a budget.

Vocabulary

Flow rate
Flow rate measures how much water moves past a point in a certain amount of time, like gallons per minute through a garden hose. Bigger pipes and stronger pushes give bigger flow rates.

Also: retrofit, low-flow, conservation

Teacher overview

Northgate Middle School, in the fictional town of Ardenwood, is planning a fixture retrofit. A retrofit swaps old fixtures for low-flow models that use less water for the same job. Standard showerheads flow at about 2.5 gallons per minute, while WaterSense-labeled models use 2.0 gallons per minute or less. Faucets can be fitted with aerators that cut their flow too.

Students compare flow rates, find the water and money saved, and fit a purchase to a budget. A common mistake is thinking that a lower flow rate means students must shorten their showers. The savings come from the flow rate itself, because gallons used equal the flow rate times the number of minutes.

Answer Key

  1. Answer: 20 gallons. 2.5 gpm x 8 minutes = 20 gallons.
  2. Answer: 16 gallons. 2.0 gpm x 8 minutes = 16 gallons.
  3. Answer: 4 gallons. 20 - 16 = 4 gallons saved per shower.
  4. Answer: 20 percent. 4 / 20 = 0.20, or 20 percent of the standard shower's water.
  5. Answer: 32 gallons. 4 gallons saved per shower x 8 showers = 32 gallons per day.
  6. Answer: $51.84. Water costs $9 / 1,000 gallons. 5,760 / 1,000 = 5.76, and 5.76 x 9 = $51.84.
  7. Answer: 0.7 gallons. 2.2 gpm - 1.5 gpm = 0.7 gallons saved each minute.
  8. Answer: 140 gallons. 0.7 gallons x 10 minutes x 20 faucets = 140 gallons per day.
  9. Answer: 10 showerheads. Solve 18n = 180 by dividing both sides by 18, so n = 10.
  10. Answer: Fewer gallons flow each minute. Gallons used equal the flow rate times the minutes, so a smaller flow rate uses fewer gallons for the same shower length, which lowers the bill.

Differentiation

Support

Give students a filled example first: a 5-minute standard shower uses 2.5 times 5, or 12.5 gallons. Provide the equation in problem 9 already set up as 18n = 180 with the hint "divide both sides by 18." Allow a calculator for the decimal steps in problems 6 and 7.

Extension

Ask students to find the total yearly water saved if the faucet aerators run every school day for 180 days, then decide which retrofit, showers or faucets, saves more water per year and justify the answer with their numbers.

ELL supports

Pre-teach "flow rate," "retrofit," and "aerator" with a picture of a showerhead and a labeled arrow showing gallons per minute. Provide a sentence frame for problem 10: "A lower flow rate saves water because ___."