Math problem set Grade 7 Math

Sable Ridge's Reverse-Osmosis Pilot: A Proportionality Problem Set

A grade 7 problem set where students test a reverse-osmosis pilot's data for proportionality, find its constant of proportionality, and write an equation.

Objectives

  1. Students will test a data table for a proportional relationship and identify the constant of proportionality.
  2. Students will write and use an equation to predict values outside a given data table.

Vocabulary

Key words: proportional relationship, constant of proportionality, permeate, reject water

Teacher overview

Sable Ridge (a fictional small water system used for this problem set) is piloting a reverse-osmosis unit that pushes brackish well water through a membrane to produce clean permeate water for the community system. Operators recorded how many gallons of permeate the pilot unit produced at four different run times, and this problem set has students check whether that data forms a proportional relationship, find the unit's constant of proportionality, and use an equation to predict output at times the operators did not directly measure. A common misconception in this math is assuming any steadily increasing data set must be proportional; a relationship is only proportional when every pair in the table reduces to the same constant ratio, which students must check rather than assume.

Answer Key

  1. Answer: 1.8 gal/min.
    9 ÷ 5 = 1.8; 18 ÷ 10 = 1.8; 27 ÷ 15 = 1.8; 36 ÷ 20 = 1.8. Every pair reduces to the same ratio, 1.8 gallons per minute.
  2. Answer: yes, proportional.
    The relationship is proportional because every gallons-to-minutes ratio in the table equals the same constant, 1.8, and the table implies a starting point of 0 gallons at 0 minutes.
  3. Answer: g = 1.8m.
    The constant of proportionality is 1.8 gallons per minute, so permeate gallons equal 1.8 times the feed time in minutes.
  4. Answer: 90 gal. g = 1.8 × 50 = 90 gallons.
  5. Answer: 324 gal. g = 1.8 × 180 = 324 gallons.
  6. Answer: 129.6 min.
    324 ÷ 2.5 = 129.6 minutes.
  7. Answer: 1.2 gal/min.
    Total feed (3 gal/min) minus permeate (1.8 gal/min) equals reject water: 3 − 1.8 = 1.2 gallons per minute.
  8. Answer: 216 gal.
    1.2 gallons per minute × 180 minutes = 216 gallons.

Differentiation

Support (below grade level)

Provide the four ratio calculations from problem 1 already completed, so students can focus on interpreting whether the relationship is proportional and on writing the equation. Give a printed equation template, "g = ___ × m," with a blank for the constant.

Extension (above grade level)

Ask students to combine the permeate equation (g = 1.8m) with a reject-water equation they write themselves (r = 1.2m) into a single equation for total feed water (f = g + r), and use it to check that the total feed at 180 minutes matches 3 gallons per minute times 180 minutes.

ELL supports

Provide a labeled diagram of the reverse-osmosis unit showing feed water entering and both permeate and reject water leaving, with the words "feed," "permeate," and "reject" defined next to each arrow. Allow students to complete problem 1's table calculations directly in the table cells rather than in full sentences.

Extensions

Have students graph the four data points from the table on a coordinate plane, draw a line through them and the origin, and check that the line's steepness matches the constant of proportionality they calculated in problem 1.