Math problem set Grade 2 Math

Water Deliveries to Quillmoor Crossing: A Grade 2 Problem Set

A town's well pump is down for a week, and eight linked problems track the cases of water delivered each day against a 200-case goal.

Objectives

  1. Students will add two-digit daily counts to build a running weekly total.
  2. Students will subtract a running total from 200 to find what is still needed.
  3. Students will compare two daily counts and state the difference.

Vocabulary

Key words: case, delivery, well pump, total, goal

Teacher overview

When a small system's well pump fails, the utility often trucks bottled water to a community center until the pump is back in service, and someone counts the cases that come off the truck each day. Every problem in this set draws on one week of those counts from a small hypothetical system, the town of Quillmoor Crossing, working toward a stated goal of 200 cases. The misconception this set is built to correct is the column habit of taking the smaller digit from the larger one regardless of position, which turns 200 minus 78 into 278. Students who write an answer larger than 200 on problem 5 should be asked whether the answer can be bigger than the number they started with.

Answer Key

  1. Answer: 60 cases. Add the two days: 26 + 34. The ones give 6 + 4 = 10, so write 0 and carry one ten. The tens give 2 + 3 + 1 = 6, so the sum is 60.
  2. Answer: 59 cases. Add the two days: 18 + 41. The ones give 8 + 1 = 9 and the tens give 1 + 4 = 5, so the sum is 59.
  3. Answer: 23 cases. This is a compare problem, so subtract: 41 - 18. Take 1 from the four tens to make 11 ones, then 11 - 8 = 3 ones and 3 - 1 = 2 tens, giving 23.
  4. Answer: 78 cases. Add two at a time: 26 + 34 = 60, then 60 + 18 = 78.
  5. Answer: 122 cases. Subtract the running total from the goal: 200 - 78. Regroup one hundred into ten tens, then one ten into ten ones, leaving 1 hundred, 9 tens, and 10 ones. Then 10 - 8 = 2 ones, 9 - 7 = 2 tens, and 1 hundred stays, giving 122.
  6. Answer: 70 cases. Add the two days: 41 + 29. The ones give 1 + 9 = 10, so write 0 and carry one ten. The tens give 4 + 2 + 1 = 7, so the sum is 70.
  7. Answer: 148 cases. Add the two part totals: 78 + 70. The tens give 7 + 7 = 14 tens, which is 140, and the 8 ones stay, giving 148.
  8. Answer: 52 cases. Subtract the week's deliveries from the goal: 200 - 148. Regroup as in problem 5 to get 1 hundred, 9 tens, and 10 ones, then 10 - 8 = 2 ones, 9 - 4 = 5 tens, and 1 - 1 = 0 hundreds, giving 52.

Differentiation

Support

Give these students base ten blocks and start them at problems 1, 2, 3, and 6, all of which stay under 100 and use one operation. For problems 5 and 8, provide a drawing of two hundred flats already traded into tens and ones so the regrouping is done for them and only the subtraction remains.

Extension

Ask students to find a different set of five daily counts that also reaches exactly 148 cases for the week, with no day above 45 cases, and to show the addition that proves it. A second challenge is to decide how many cases the truck must bring on Saturday to reach the 200-case goal, and to write the number sentence.

ELL supports

Show a photograph of a pallet of bottled water cases and count three cases aloud so the unit is concrete before the reading begins. Post the sentence frames "The truck brought ___ cases," and "The town still needs ___ cases," and highlight the words "in all" and "how many more" in different colors, since those phrases decide the operation in most problems.

Extensions

Have students plan a delivery week of their own for the town of Quillmoor Crossing, choosing five daily counts that add to exactly 200 cases with no day above 50, then trade plans with a partner and check the partner's total. Building a week backward from the goal turns the same numbers into missing addend reasoning without introducing any new operation.