Math problem set Grade 6 Math

Harlow Home Reverse-Osmosis Recovery Ratio Problems

A grade 6 problem set on a fictional family's under-sink reverse-osmosis filter, using ratios and percent to compare clean water made with water sent to the drain.

Objectives

  1. Students will write the clean-to-drain ratio for a reverse-osmosis filter and find its recovery percent.
  2. Students will use ratio tables to compare how much water two filters use to make the same clean amount.

Vocabulary

Reverse osmosis
Reverse osmosis cleans water by pushing it through a membrane with holes so tiny that salt and most other dissolved things cannot fit through. It can even turn seawater into fresh water.

Also: ratio, percent, recovery

Teacher overview

A reverse-osmosis filter pushes tap water through a very fine membrane. Some water comes out clean, and the rest carries the trapped minerals to the drain. This problem set follows the Harlow family, a fictional family with an under-sink filter, and builds the idea of "recovery," the share of water that becomes clean. A common mistake to watch for is thinking recovery means all the water is saved; only the clean fraction is recovered, and the drain share is real water too. Watch also for students who mix up the clean amount with the drain amount in the ratio.

Answer Key

  1. Answer: 1 : 3. For every 1 clean gallon there are 3 drain gallons, and 1 : 3 is already in simplest form.
  2. Answer: 25 percent. 1 clean gallon out of 4 total gallons in is 1 ÷ 4 = 0.25, or 25 percent.
  3. Answer: 75 percent. 3 drain gallons out of 4 total is 3 ÷ 4 = 0.75, or 75 percent.
  4. Answer: 24 gallons. It takes 4 tap gallons for each clean gallon, so 6 × 4 = 24 gallons.
  5. Answer: 18 gallons. Of the 24 gallons in, 6 came out clean, so 24 − 6 = 18 gallons to the drain (or 6 × 3 = 18).
  6. Answer: 8; 20; 40. At 4 tap gallons for each clean gallon: 2 × 4 = 8, 5 × 4 = 20, 10 × 4 = 40 gallons.
  7. Answer: 50 percent. 1 clean gallon out of 2 gallons in is 1 ÷ 2 = 0.5, or 50 percent.
  8. Answer: 40 gallons old, 20 gallons new, saves 20 gallons. Old filter: 10 × 4 = 40; newer filter: 10 × 2 = 20; 40 − 20 = 20 gallons saved.
  9. Answer: Recovery is the ratio of clean water to the total water that enters the filter; here 1 clean gallon for every 4 gallons in, so the recovery is 1 out of 4.
  10. Answer: 75 percent. The drain share is 75 percent, so reusing all of it means that 75 percent is no longer wasted.

Differentiation

Support

Give students 4 counters to model each cycle: 1 marked "clean" and 3 marked "drain." Have them act out problems 4 and 5 by making stacks before they multiply. Provide the reminder "percent = part ÷ whole × 100" on a printed strip.

Extension

Ask students to find what recovery percent a filter would have if it made 2 clean gallons for every 5 gallons of tap water, and to compare that filter with the old and newer filters in this set. Have them rank the three filters from most to least wasteful.

ELL supports

Pre-teach "clean water," "drain," "ratio," and "recovery" with a simple diagram showing tap water splitting into a clean stream and a drain stream. Provide a sentence frame for problem 9: "Recovery is the ratio of ___ to ___." Allow counters or drawings as shown work.