Lesson plan Grade 8 Math
Pinewick Well Drawdown: Building a Linear Function
A 50-minute grade 8 lesson where students build and interpret a linear function for the water depth in a fictional well as its pump draws the level down.
Objectives
- Students will construct a linear function for a well's water depth from a rate and a starting value.
- Students will interpret the rate of change and initial value of the function in context.
Vocabulary
- Drawdown
- Drawdown is how far the water level in a well drops when a pump pulls water out. The harder and longer you pump, the bigger the drawdown gets.
Also: linear function, rate of change, initial value
Teacher overview
The fictional Pinewick well field draws drinking water from an aquifer. Before a pump starts, the water sits at a resting depth called the static level. Once the pump runs, the water level drops a little deeper each hour, a change called drawdown, which makes the depth a linear function of pumping time. In a real well the drop is fastest at first and then slows, so the steady rate used here is a simplified model. This lesson has students build that function and read its parts. A common misconception is treating the starting depth as the rate; students should see the static level as the initial value and the steady per-hour drop as the rate of change.
Procedure
Hook (5 min): Ask students what they think happens to the water level inside a well while a pump is running. Collect a few predictions, then confirm that the level drops, which is why operators watch it closely, and explain that this lesson treats the drop as steady to build a simple model.
Direct instruction (12 min): Model a linear function with a demonstration well that is not on the handout. This demo well has a static depth of 20 feet, and the water drops 1 foot each hour of pumping. Build the function D = 20 + t together, and label 20 as the initial value (the static level) and 1 as the rate of change (the drawdown rate). Evaluate it at 4 hours to get 24 feet.
Guided practice (13 min): As a class, change the demo well's drawdown rate to 2 feet per hour and rewrite the function as D = 20 + 2t. Ask a check-for-understanding question: "Which number changed, the initial value or the rate of change?" Expect students to identify that only the rate of change changed. Evaluate the new function at 5 hours together.
Independent practice (15 min): Students complete the Student Handout for the Pinewick well and a second well, building and interpreting each linear function.
Closure and exit ticket (5 min): On an index card, students write the function for a well with a static depth of 35 feet that drops 2 feet per hour, then find the depth after 3 hours. Collect and check that the function is D = 35 + 2t and the depth is 41 feet.
Student Handout
Use the fictional Pinewick well. Its static depth to water is 40 feet. While the pump runs, the water drops 2 feet deeper each hour. Let t stand for hours of pumping and D for the depth to water in feet.
- Write a linear function for the depth to water, D, after t hours of pumping.
- State the rate of change and the initial value of your function, and explain what each one means for the well.
- What is the depth to water after 6 hours of pumping?
- The pump must shut off before the water reaches 70 feet deep. After how many hours does the water reach 70 feet?
- A second well, Well B, has a static depth of 30 feet and drops 3 feet each hour, so its function is D = 30 + 3t. What is Well B's depth after 6 hours?
- After 6 hours, which well has water closer to the surface, and by how many feet?
- Explain your reasoning: What does a larger drawdown rate tell you about how quickly a well's water level is falling?
From Water for Schools (waterforschools.org). This material is in the public domain (CC0) and may be copied, edited, and shared freely.
Answer Key
- Answer: D = 40 + 2t.
Start at the static depth of 40 feet and add 2 feet for each hour t, so D = 40 + 2t. - Answer: rate of change 2 feet per hour, initial value 40 feet.
The rate of change is 2 feet per hour, the drawdown rate the water drops while pumping. The initial value is 40 feet, the static depth before the pump starts. - Answer: 52 feet.
D = 40 + 2(6) = 40 + 12 = 52 feet. - Answer: 15 hours.
40 + 2t = 70. Subtract 40: 2t = 30. Divide by 2: t = 15 hours. - Answer: 48 feet.
D = 30 + 3(6) = 30 + 18 = 48 feet. - Answer: Well B by 4 feet.
Well B is at 48 feet and Pinewick is at 52 feet, so Well B's water is closer to the surface by 52 - 48 = 4 feet. - Answer: A larger drawdown rate means the water level is falling faster, so the depth increases more for each hour of pumping and the well reaches its shut-off depth sooner.
Differentiation
Support
Provide the function form D = (initial value) + (rate) times t as a fill-in template, and pre-label the static level and drawdown rate for the Pinewick well before item 1. Allow a calculator for every computation item.
Extension
Ask students to find the drawdown rate a well would need so that, starting from a static depth of 40 feet, it reaches 70 feet in exactly 10 hours, then write and check the function.
ELL supports
Pre-teach "static level," "drawdown," and "depth to water" with a labeled cross-section of a well showing the resting water line and a lower pumping water line. Provide a sentence frame for item 2: "The rate of change is ___, which means ___; the initial value is ___, which means ___."