Quiz & test questions Grade 9 Math

Kestrel Bend Water Plant: A Grade 9 Treatment Math Quiz

A 30-point grade 9 quiz mixing multiple-choice, short-answer, and computation items on dosing, detention time, removal efficiency, and pressure at a fictional plant.

Objectives

  1. Students will apply the pounds formula, detention time, and removal efficiency to plant data.
  2. Students will convert between units and between feet of head and psi.

Vocabulary

Detention time
Detention time is how long water stays inside a tank or basin before flowing out. Water must stay long enough for each treatment step, like settling or disinfecting, to finish its job.
Turbidity
Turbidity is a measure of how cloudy or murky water looks because of tiny particles floating in it. Clear water has low turbidity, and muddy water has high turbidity.

Also: pounds formula, removal efficiency

Teacher overview

This 35-minute quiz is worth 30 points and checks whether students can apply core water-treatment math at a grade 9 level. It mixes multiple-choice, short-answer, and computation items built around one fictional plant, so students reuse the same flow across several formulas. The items cover the pounds formula, detention time, removal efficiency, a turbidity standard, and a pressure conversion, and they range from recall to multi-step application.

Answer Key

  1. Answer: A) dose (mg/L) x flow (MGD) x 8.34. This is the pounds formula, which multiplies concentration, flow in MGD, and the constant 8.34 pounds per gallon.
  2. Answer: 83.4 lbs/day. Feed = 2.5 mg/L x 4.0 MGD x 8.34 = 10 x 8.34 = 83.4 pounds per day.
  3. Answer: 1.44 hours. Detention = 240,000 gallons / 4,000,000 gallons per day = 0.06 day; 0.06 x 24 = 1.44 hours.
  4. Answer: B) shorter than typical. The 1.44-hour detention time is below the usual 2-to-4-hour design range for sedimentation.
  5. Answer: 96 percent. (5.0 - 0.2) / 5.0 x 100 = 4.8 / 5.0 x 100 = 96 percent.
  6. Answer: Yes. The finished value of 0.2 NTU is at or below the 0.3 NTU limit, so this sample meets the rule.
  7. Answer: 56.3 psi. 130 feet x 0.433 psi per foot = 56.29, which rounds to 56.3 psi.
  8. Answer: 2,776 gpm. 4.0 MGD x 694 gpm per MGD = 2,776 gallons per minute.
  9. Answer: 3.0 mg/L. The equation is F = D x 4.0 x 8.34 = 33.36D. Set 33.36D = 100; D = 2.998, about 3.0 mg/L.

Differentiation

Support

Provide a formula card listing the pounds formula, detention time, removal efficiency, and the 0.433 psi-per-foot conversion, each with units labeled. Pre-fill the first multiplication step for item 2, and allow calculators on all computation items.

Extension

Ask students to find the clarifier volume, in gallons, that would give exactly 2 hours of detention at the plant's 4.0 MGD flow, working backward from the detention-time formula, and to state whether that is larger or smaller than the current 240,000-gallon clarifier.

ELL supports

Provide a labeled plant diagram (intake, clarifier, filters, tank) so item numbers map to a place students can see. Pre-teach "detention time," "removal efficiency," and "turbidity," and allow item 6 to be answered with a sentence frame: "The value of 0.2 NTU is ___ the 0.3 NTU limit, so it ___ the rule."