Worksheet Grade 9 Science

Chlorine Contact Time at Merrowfield: A Grade 9 CT Worksheet

A grade 9 worksheet where students find contact time from basin volume and flow, calculate CT for disinfection, and solve for the residual a plant needs at peak flow.

Objectives

  1. Students will calculate a contact basin's contact time from its volume and flow rate.
  2. Students will calculate CT as the product of chlorine residual and contact time.
  3. Students will solve for the residual needed to meet a required CT at a higher flow.

Vocabulary

Chlorine residual
Chlorine residual is the small amount of chlorine still left in the water after it leaves the treatment plant. It keeps protecting the water from germs all the way to your faucet.
CT value
CT value is a way operators check that water has been disinfected long enough. It is found by multiplying how much disinfectant is in the water by how many minutes the water has been in contact with it.
Disinfection
Disinfection is the step that kills or disables germs in water so it is safe to drink. Water plants usually disinfect with chlorine, ultraviolet light, or ozone.

Also: contact time, contact basin

Teacher overview

Chlorine needs time in contact with water to kill or inactivate germs, so treatment plants send water through a contact basin before it reaches homes. Operators track a number called CT, the chlorine residual multiplied by the contact time, because a required CT stands for enough disinfection. This worksheet has students calculate contact time and CT for the fictional plant at Merrowfield, then see what happens when the flow speeds up. A common error is to assume that a higher flow gives more disinfection; a higher flow actually shortens the contact time and lowers CT.

Answer Key

  1. Answer: 100 min.
    Contact time = 50,000 gallons divided by 500 gpm = 100 minutes.

  2. Answer: 80 mg/L-min.
    CT = 0.8 mg/L x 100 minutes = 80 mg/L-min.

  3. Answer: Yes, by 20 mg/L-min.
    80 mg/L-min is above the required 60 mg/L-min, so the plant meets the requirement with a margin of 80 minus 60 = 20 mg/L-min.

  4. Answer: 62.5 min.
    Contact time = 50,000 gallons divided by 800 gpm = 62.5 minutes.

  5. Answer: 50 mg/L-min.
    CT = 0.8 mg/L x 62.5 minutes = 50 mg/L-min.

  6. Answer: No, short by 10 mg/L-min.
    50 mg/L-min is below the required 60 mg/L-min, so the plant falls short by 60 minus 50 = 10 mg/L-min at peak flow.

  7. Answer: 0.96 mg/L.
    Residual = CT divided by contact time = 60 mg/L-min divided by 62.5 minutes = 0.96 mg/L.

  8. Answer: Higher flow shortens contact time, which lowers CT; operators can raise the residual or slow the flow.
    CT depends on contact time, and contact time is volume divided by flow. When flow rises, the water spends less time in the fixed basin, so contact time and CT both drop. To restore CT, operators could raise the chlorine residual, reduce the flow through the basin, or add basin volume so water stays longer.

Differentiation

Support

Provide the contact-time and CT formulas already written with labeled blanks for volume, flow, residual, and time. Work item 1 and item 2 together as a pair so students see the two-step order before repeating it for the peak-flow case.

Extension

Ask students to find the highest flow, in gallons per minute, at which the plant can still meet the required CT while holding the same chlorine residual, working backward from the CT requirement to a contact time and then to a flow.

ELL supports

Pre-teach "residual," "contact time," and "CT" with a simple diagram: water enters the basin, chlorine stays in contact for a set time, and CT combines the two. Provide a sentence frame for item 8: "Higher flow lowers CT because ___."