Quiz & test questions Grade 6 Engineering & Design

Marne Water Plant Settling Basin Design Assessment

A grade 6 engineering assessment where students size a rectangular settling basin, find detention time and removal percent, and pick a design change to meet a goal.

Objectives

  1. Students will calculate the volume of a rectangular settling basin in cubic feet and gallons.
  2. Students will find detention time and removal percent and select a design change to meet a goal.

Vocabulary

Detention time
Detention time is how long water stays inside a tank or basin before flowing out. Water must stay long enough for each treatment step, like settling or disinfecting, to finish its job.
Turbidity
Turbidity is a measure of how cloudy or murky water looks because of tiny particles floating in it. Clear water has low turbidity, and muddy water has high turbidity.

Also: settling basin, removal efficiency

Teacher overview

This 30-minute assessment (30 points total) checks whether students can size a settling basin and reason about its performance. A settling basin is a large tank where heavy dirt sinks to the bottom before water moves on to the filters. The assessment mixes two multiple-choice items, two short-answer items, and five computation items built around a fictional town's water plant.

Answer Key

  1. Answer: B. Heavy dirt settles to the bottom of the basin, which is how a settling basin removes it before filtering.
  2. Answer: 8,400 cubic feet. V = 40 x 20 x 10.5 = 8,400 cubic feet.
  3. Answer: 62,832 gallons. 8,400 cubic feet x 7.48 gallons per cubic foot = 62,832 gallons.
  4. Answer: 3.9 hours. 62,832 gallons / 16,000 gallons per hour = 3.927, which rounds to about 3.9 hours.
  5. Answer: 97.5 percent. (12 - 0.3) / 12 x 100 = 11.7 / 12 x 100 = 97.5 percent removed.
  6. Answer: Yes. About 3.9 hours falls between 2 and 4 hours, so the basin's detention time is within the typical design range.
  7. Answer: B. Detention time equals volume divided by flow, so a lower flow makes the water stay in the basin longer.
  8. Answer: Make the basin bigger or slow the flow. A larger volume or a smaller flow raises volume divided by flow, so detention time goes up and dirt has more time to settle. Accept either change with a matching reason.
  9. Answer: 3,600 cubic feet. V = 30 x 15 x 8 = 3,600 cubic feet.

Differentiation

Support

Provide the volume formula and the gallons conversion on a reference strip, and set up item 2 as 40 x 20 x 10.5 so students only carry out the multiplication. Allow a calculator for every computation item.

Extension

Ask students to find the flow, in gallons per hour, that would give the 62,832-gallon basin exactly 3 hours of detention, then explain whether raising or lowering the flow from 16,000 gallons per hour gets there.

ELL supports

Provide a labeled sketch of a settling basin showing water in, dirt settling to the bottom, and cleaner water leaving. Pair "settle," "detention time," and "removal" with the picture, and give a sentence frame for item 6: "About 3.9 hours is ___ the typical range because ___."