Math problem set Grade 6 Engineering & Design

Pinebrook Garden Club Irrigation Pump Selection Problems

Eight problems where a fictional garden club compares two irrigation pumps' unit rates, solving one-step equations to find pumping time and check a time rule.

Objectives

  1. Students will identify each pump's unit rate in gallons per minute and use it to compare pumping times.
  2. Students will write and solve one-step equations of the form px = q to find how long a pump takes to deliver a given amount of water.
  3. Students will check a pump's performance against a stated time constraint.

Vocabulary

Key words: unit rate, equation, constraint

Teacher overview

The Pinebrook Middle School garden club (a fictional club used for this problem set) is choosing an irrigation pump for its raised garden beds and is comparing two pump options by their unit rate in gallons per minute. This problem set uses each pump's rate to find pumping time through one-step equations, then checks the results against the club's own time rule. A common misconception in this set is solving an equation like 3t = 150 by subtracting 3 from 150 instead of dividing 150 by 3; watch for that error, since dividing by the rate is the only operation that isolates the pumping time.

Answer Key

  1. Answer: 50 minutes. 3t = 150, so t equals 150 divided by 3, which is 50 minutes.
  2. Answer: 30 minutes. 5t = 150, so t equals 150 divided by 5, which is 30 minutes.
  3. Answer: 20 minutes. 50 minus 30 equals 20 fewer minutes for Pump B.
  4. Answer: $25. $70 minus $45 equals $25.
  5. Answer: 100 minutes. 3t = 300, so t equals 300 divided by 3, which is 100 minutes.
  6. Answer: 60 minutes. 5t = 300, so t equals 300 divided by 5, which is 60 minutes.
  7. Answer: Pump A does not meet the rule; Pump B does. Pump A's 50 minutes (problem 1) is longer than the 45-minute limit, while Pump B's 30 minutes (problem 2) is under the limit.
  8. Answer: No, it could not. A pump can only move as much water as its water source supplies, so if the spigot supplies water at a maximum of 6 gallons per minute, a pump rated for 7 gallons per minute is limited to the spigot's 6-gallon-per-minute rate; the spigot becomes the binding constraint regardless of the pump's own rating.

Differentiation

Support

Provide a filled-in example equation, 4t = 200, solved step by step (t equals 200 divided by 4, which is 50), as a model before students solve problems 1, 2, 5, and 6 on their own, and allow a calculator for every division step.

Extension

Ask students to find a pump rate, in whole gallons per minute, that would deliver 150 gallons in exactly 25 minutes, using the equation rt = 150 and solving for r.

ELL supports

Pre-teach "rate," "equation," and "constraint" using a simple diagram of a hose filling a bucket, with an arrow labeled "gallons per minute" pointing into the bucket. Allow students to show equation work as numbers on a simple two-line solution, the equation and then the answer, rather than full sentences.

Extensions

Have students research, using only teacher-provided rate cards, a third real garden-hose flow rate and calculate how long it would take to deliver the same 150 gallons, adding it to a class comparison table of pump and hose options.