Worksheet Grade 8 Engineering & Design

Belmoor's Water-Main Replacement Budget: A Linear Function Worksheet

A grade 8 worksheet where students build linear cost functions for replacing aging water mains, solve for feet within a budget, and compare two contracts.

Objectives

  1. Students will write a linear cost function from a setup fee and a per-foot rate.
  2. Students will solve a linear equation to find how many feet of main a budget can replace, and compare two contracts.

Vocabulary

Water main
A big underground pipe that carries drinking water beneath the streets to a neighborhood. Smaller service lines branch off it to reach each building.

Also: linear function, setup fee, per-foot rate, budget

Teacher overview

Many US water systems run on old pipes, and the strain shows: the ASCE 2025 report card gave the nation's drinking water a C-, and a water main breaks somewhere in the country about every two minutes. This worksheet puts students in the role of a utility planner for a fictional town that must replace aging mains on a fixed budget. Students build a linear cost function, solve for how many feet a budget covers, and compare two contractor offers. The cost model uses a setup fee that is paid once plus a steady price for each foot of pipe.

Answer Key

  1. Answer: C = 60f + 5,000.
    The per-foot rate is $60 (the slope) and the one-time setup fee is $5,000 (the starting value), so C = 60f + 5,000.

  2. Answer: $77,000.
    C = 60 x 1,200 + 5,000 = 72,000 + 5,000 = 77,000 dollars.

  3. Answer: $155,000.
    C = 60 x 2,500 + 5,000 = 150,000 + 5,000 = 155,000 dollars.

  4. Answer: 3,000 ft.
    Set C = 185,000: 60f + 5,000 = 185,000, so 60f = 180,000 and f = 3,000 feet.

  5. Answer: 33%.
    3,000 feet divided by 9,000 feet = 0.333, which rounds to about 33 percent of the town's old main.

  6. Answer: 3 years.
    9,000 feet divided by 3,000 feet each year = 3 years.

  7. Answer: C = 50f + 8,000.
    The per-foot rate is now $50 and the setup fee is $8,000, so C = 50f + 8,000.

  8. Answer: $158,000.
    C = 50 x 3,000 + 8,000 = 150,000 + 8,000 = 158,000 dollars, which is 27,000 dollars under the 185,000-dollar budget.

  9. Answer: 3,540 ft.
    Set C = 185,000: 50f + 8,000 = 185,000, so 50f = 177,000 and f = 3,540 feet.

  10. Answer: The second contractor.
    The second contractor replaces 3,540 feet for the budget, while the first replaces 3,000 feet, so the second contractor covers 540 more feet for the same 185,000 dollars.

Differentiation

Support

Give students the first cost function C = 60f + 5,000 already written and a filled example (replacing 1,000 feet) worked out, so they can focus on items 2 through 4. Allow calculators and provide a number line showing the budget as a ceiling.

Extension

Ask students to find the number of feet at which both contractors cost exactly the same, by setting 60f + 5,000 equal to 50f + 8,000 and solving, then explain which contractor is cheaper below and above that point.

ELL supports

Pre-teach setup fee as "paid one time" and per-foot rate as "paid for each foot" using a simple labeled drawing of a pipe. Provide the sentence frame "The cost is ___ for each foot plus a one-time fee of ___."