Lab / experiment Grade 12 Science

Quarryhill Soap Titration: Calibrating a Water Hardness Test

A grade 12 chemistry lab where students calibrate a soap titration with Epsom-salt standards, estimate tap-water hardness as CaCO3, and check it against EDTA.

Objectives

  1. Students will prepare Epsom-salt standards and calculate their hardness in mg/L as calcium carbonate from mass, molar mass and dilution.
  2. Students will write balanced molecular and net ionic equations for the precipitation of magnesium and calcium soaps.
  3. Students will build a soap-titration calibration line, check it with residuals, and use it to estimate the hardness of tap water and a diluted well sample with a stated uncertainty.
  4. Students will evaluate the soap estimate against test-strip and EDTA titration results and explain sources of bias.

Vocabulary

Key words: hardness, standard solution, calibration curve, net ionic equation, residual, EDTA titration

Teacher overview

Hardness is the dissolved calcium and magnesium in water, which utilities report in milligrams per liter as calcium carbonate (mg/L as CaCO3). Before EDTA titration became the standard laboratory test, chemists measured hardness by soap titration: each hardness ion precipitates two soap anions as scum, so a sample will not hold a lather until its hardness has been used up, and the soap consumed tracks the hardness present. In this lab students turn that reaction into a calibrated measurement. They weigh Epsom salt to make a stock solution, dilute it into six standards from 0 to 250 mg/L as CaCO3, fit a calibration line to their drop counts, and use the line to estimate the hardness of their own tap water.

The analysis is worked first on a reference data set from a fictional chemistry class at Quarryhill High School, along with a fictional Quarryhill Water Department report that gives an EDTA result for the same tap water, so students can check their method against the key and then apply it to their own data. The soap method is a teaching version of a historical test, not a certified measurement, and part of the work is deciding how far its result can be trusted. Teachers should note that the calibration standards contain only magnesium while most tap-water hardness is calcium; item 8 asks students to reason about that mismatch.

Answer Key

  1. Answer: 999 mg/L as CaCO3 for the stock, and 150 mg/L as CaCO3 for S150.
    Moles of Epsom salt = 1.23 g ÷ 246.47 g/mol = 0.004990 mol. Each formula unit releases one Mg2+, so the stock holds 0.004990 mol ÷ 0.5000 L = 0.009981 mol/L of Mg2+. Counting each mole as one mole of CaCO3 gives 0.009981 mol/L × 100.09 g/mol = 0.9990 g/L, or 999 mg/L as CaCO3. Carrying the unrounded stock value, S150 = 998.99 mg/L × (15.0 mL ÷ 100.0 mL) = 149.85 mg/L, which rounds to 150 mg/L, the value in the standards table. The crystals weighed on the balance include seven waters of hydration, so the mass of each formula unit is 246.47 g/mol. A student who uses anhydrous MgSO4, 120.37 g/mol, counts the water as if it were magnesium salt and gets about 2,046 mg/L as CaCO3, roughly twice the true value.

  2. Answer: MgSO4(aq) + 2 C17H33COOK(aq) → Mg(C17H33COO)2(s) + K2SO4(aq); net ionic, Mg2+(aq) + 2 C17H33COO-(aq) → Mg(C17H33COO)2(s); for calcium, Ca2+(aq) + 2 C17H33COO-(aq) → Ca(C17H33COO)2(s).
    The spectator ions are K+ and SO4 2-. Lather depends on free oleate anions gathering at the air-water surface around each bubble. While Mg2+ or Ca2+ remains in solution, each added oleate anion is removed into the insoluble scum, two anions per hardness ion, so the foam collapses. Only after essentially all the hardness ions have been precipitated does free oleate build up in solution and hold a lather. Because the soap removed is a fixed two anions per hardness ion, the drops consumed rise in proportion to the hardness. Accept equations written with sodium in place of potassium if the student states that assumption.

  3. Answer: y = 0.0990x + 3.84, with r = 0.999, where y is mean drops and x is hardness in mg/L as CaCO3.
    The means are 4.00, 8.67, 13.67, 19.00, 23.00 and 29.00 drops. With x-bar = 125 and y-bar = 16.22, Sxx = 43,750 and Sxy = 4,333.3, so the slope = 4,333.3 ÷ 43,750 = 0.0990 drops per mg/L, and the intercept = 16.22 − 0.09905 × 125 = 3.84 drops. The slope means each extra 1 mg/L as CaCO3 of hardness in a 25.0 mL sample uses about 0.099 more drop of soap, or about one drop for every 10 mg/L. The intercept is the soap a sample with no hardness still needs, because soap must reach a minimum free concentration before it can hold a foam. That is why distilled water takes about four drops, and why an unknown's hardness is calculated from the drops above the intercept rather than from its total drops. A regression on all eighteen individual trials gives the same slope and intercept, with a lower r of 0.996, which is also acceptable if the student says which points were used.

  4. Answer: The residuals are +0.16, −0.12, −0.07, +0.31, −0.64 and +0.41 drops, and the largest is −0.64 drops at 200 mg/L as CaCO3.
    The predicted values from y = 0.0990x + 3.84 are 3.84, 8.79, 13.74, 18.69, 23.64 and 28.59 drops, and each residual is the observed mean minus that value (for example, 23.00 − 23.64 = −0.64). Every residual is smaller than one drop, which is the counting resolution of the test, and the positive and negative signs are mixed with no curved pattern, such as positive residuals at both ends with negative ones in the middle. A straight line is a reasonable model from 0 to 250 mg/L as CaCO3. The residuals say nothing about how the test behaves above 250 mg/L.

  5. Answer: 123 mg/L as CaCO3, from a mean of 16.0 drops with a standard deviation of 0.816 drops.
    Mean = (16 + 15 + 17 + 16) ÷ 4 = 16.0 drops. The deviations are 0, −1, +1 and 0, the sum of squares is 2, and the sample standard deviation is the square root of 2 ÷ 3, or 0.816 drops. Solving the calibration line for x gives x = (16.0 − 3.84) ÷ 0.0990 = 12.16 ÷ 0.0990 = 122.8, which rounds to 123 mg/L as CaCO3. For a student's own data, check that the hardness was found from the drops above the intercept and that the mean falls inside the calibrated range.

  6. Answer: 8.2 mg/L as CaCO3; report the tap water as about 120 mg/L as CaCO3, which the soap test cannot place securely on either side of the moderately hard and hard boundary.
    0.816 drops ÷ 0.0990 drops per mg/L = 8.2 mg/L as CaCO3 for the spread of a single trial. The test counts whole drops, and one drop is worth about 10 mg/L, so a value such as 122.8 or even 123 claims more precision than the method has. A defensible report is about 120 mg/L, give or take about 8 mg/L. The estimate plus or minus one spread, roughly 115 to 131 mg/L, crosses the line between moderately hard (61 to 120) and hard (121 to 180), so the classification is not settled by this test alone. Accept "123 ± 8 mg/L" as the reported value if the student explains that the last digit is uncertain and reaches the same conclusion about the classification.

  7. Answer: 333 mg/L as CaCO3, which is very hard.
    The undiluted mean is 42.0 drops, far above the 29.00-drop mean of the highest standard. Using the line there would be extrapolation beyond 250 mg/L, where the residuals in item 4 give no evidence that the response stays linear. The 1:1 dilution halves the concentration and brings the count back inside the calibrated range. The diluted mean is (20 + 21 + 20) ÷ 3 = 20.33 drops, so the diluted sample is (20.33 − 3.84) ÷ 0.0990 = 16.49 ÷ 0.0990 = 166.6 mg/L, and the original well water is 2 × 166.6 = 333 mg/L as CaCO3, above the 180 mg/L limit for very hard. Doubling the drops first, 2 × 20.33 = 40.67 drops, also doubles the blank of about 3.84 drops that any 25.0 mL sample needs before it can lather, so the blank is counted twice. That route gives (40.67 − 3.84) ÷ 0.0990 = 372 mg/L, which is too high.

  8. Answer: −6.1 percent; the soap estimate is 6.1 percent below the EDTA result.
    Percent difference = (123 − 131) ÷ 131 × 100 = −8 ÷ 131 × 100 = −6.1 percent. The 8 mg/L gap is about the same as the 8.2 mg/L spread of a single soap trial from item 6, so the soap result agrees with EDTA within the soap method's own precision. The strips agree as well, though they only show that the water lies nearer the 120 block than the 50 or 250 blocks. Accept any two well-reasoned sources of bias, for example: the standards contain only magnesium, while the report shows that 97 of the 131 mg/L, about three quarters, is calcium, and calcium and magnesium soaps do not form at the same rate or with the same solubility, so a magnesium calibration may not respond the same way to calcium-rich water; judging when the lather "lasts" is a human decision that can drift between trials; drop size changes with how the bottle is held; and the soap reagent's strength can change if it is stored or remixed. EDTA is the reference method because it binds each Ca2+ or Mg2+ ion in a fixed 1:1 ratio, the volume of titrant can be measured precisely, and an indicator gives a sharp color change, while the soap endpoint depends on a judgment of foam and the strips report only coarse color blocks. A strong answer proposes a fix, such as adding calcium standards to the calibration.

Differentiation

Support

Work item 1 together as a class before anyone weighs salt, and post the standards table where every group can see it. Provide a spreadsheet template with the six standard concentrations already entered, so students type their mean drop counts and read the slope, intercept and r from the regression output. For item 2, give students the skeleton "M2+(aq) + 2 ____ → ____(s)" and have them fill in magnesium first, then calcium. For item 5, write the rearranged equation x = (y − intercept) ÷ slope on the board.

Extension

Have students build a second calibration from food-grade calcium chloride (sold as a canning firming agent), working out from the package label whether the product is anhydrous or a hydrate before they calculate the stock concentration. They then compare the calcium and magnesium slopes, decide whether the magnesium-only calibration pushed the Quarryhill tap estimate high or low, and recalculate the tap-water hardness with a calibration that matches the report's calcium-to-magnesium ratio.

ELL supports

Provide a labeled photo of a "lasting lather," an unbroken foam layer across the surface, next to a photo of scattered bubbles that break quickly. Give a word bank for item 2 (precipitate, spectator ion, oleate anion, insoluble) and sentence frames for item 3: "The slope means that each extra ___ mg/L of hardness needs ___ more drops of soap," and "The intercept means that water with no hardness still needs ___ drops because ___." Allow students to answer item 8 with a short labeled list of reasons rather than a paragraph.

Extensions

Students can use the slope from the fictional Quarryhill reference data to estimate the strength of the soap reagent itself. One mg/L as CaCO3 in a 25.0 mL sample is 2.50 × 10^-7 mol of hardness ion, so a slope of 0.0990 drops per mg/L means each drop precipitates about 2.52 × 10^-6 mol of Mg2+ and therefore carries about 5.0 × 10^-6 mol of oleate. Students then repeat the calculation with their own group's slope, count the drops their own bottle delivers into 2.0 mL of a 10 mL graduated cylinder, and convert the moles per drop into a molar concentration for the reagent. Because every group used the same soap batch, the concentrations should roughly agree while the drops per milliliter differ from bottle to bottle, which shows why each group calibrates its own dropper.