Math problem set Grade 4 Math
Ashford Pump Station: Gallons and Minutes Multiplication
A grade 4 problem set at the fictional Ashford pump station, using multi-digit multiplication to find total gallons pumped from a flow in gallons per minute.
Objectives
- Students will multiply a flow in gallons per minute by a number of minutes to find total gallons.
- Students will solve multistep problems that combine or compare two pumps.
Vocabulary
Key words: flow, product, area model
Teacher overview
The fictional town of Ashford runs a pump station with three pumps, each moving a set number of gallons each minute. This set has students find total gallons by multiplying a flow by a number of minutes, using the multi-digit multiplication of 4.NBT.B.5 and the multistep reasoning of 4.OA.A.3. Problems 2, 4, 6, and 8 reuse the pump flows given in problems 1 and 3, so students should work in order. A common error is adding the flow and the minutes instead of multiplying them; remind students that a rate repeated over many minutes calls for multiplication, not addition.
Problems
The town of Ashford runs a pump station. Each pump moves the same number of gallons each minute in every problem. Find the total gallons.
- Pump A moves 40 gallons each minute. How many gallons does it move in 6 minutes?
- Pump A runs for 30 minutes. How many gallons is that in all?
- Pump B moves 125 gallons each minute. How many gallons in 8 minutes?
- Pump B runs for 7 minutes. How many gallons is that?
- Pump C moves 1,200 gallons each minute. How many gallons in 5 minutes?
- Pump A and Pump B each run for 1 minute. How many gallons do they move together?
- Draw an area model for 40 × 6. What is the product?
- Pump A runs for 15 minutes, then 15 minutes more. How many gallons in all?
- In 4 minutes, which pump moves more, Pump A at 40 gallons each minute or Pump B at 125 gallons each minute? By how many gallons?
From Water for Schools (waterforschools.org). This material is in the public domain (CC0) and may be copied, edited, and shared freely.
Answer Key
- Answer: 240 gallons. 40 × 6 = 240 gallons.
- Answer: 1,200 gallons. 40 × 30 = 1,200 gallons.
- Answer: 1,000 gallons. 125 × 8 = 1,000 gallons.
- Answer: 875 gallons. 125 × 7 = 875 gallons.
- Answer: 6,000 gallons. 1,200 × 5 = 6,000 gallons.
- Answer: 165 gallons. Pump A moves 40 and Pump B moves 125 in one minute, so 40 + 125 = 165 gallons.
- Answer: 240 gallons. Students may draw a rectangle labeled 6 by 40 and write 240 inside, since 40 × 6 = 240.
- Answer: 1,200 gallons. 15 + 15 = 30 minutes, and 40 × 30 = 1,200 gallons.
- Answer: Pump B, by 340 gallons. Pump A moves 40 × 4 = 160 gallons and Pump B moves 125 × 4 = 500 gallons, so B moves 500 − 160 = 340 more gallons.
Differentiation
Support
Give students a printed area-model grid and a multiplication chart. Start with problems 1 and 3, which use a one-digit number of minutes, before the two-digit problems. Let students break 30 minutes into 3 tens when they multiply in problem 2.
Extension
Ask students to find how many minutes Pump B must run to move exactly 1,000 gallons if it moves 125 gallons each minute, then check the answer by multiplying back.
ELL supports
Provide a labeled picture of a pump with an arrow showing water moving out each minute. Give a sentence frame for the word problems: "The pump moves ___ gallons each minute for ___ minutes, so I multiply to get ___ gallons."