Math problem set Grade 4 Math

Turnbull Meter Route: Multiplying and Dividing House Counts

A grade 4 problem set following a fictional water meter technician's route, multiplying houses per street and dividing a route total across a work week.

Objectives

  1. Students will multiply two two-digit numbers to find the houses on a meter route.
  2. Students will divide a four-digit total by a one-digit number and name the remainder.
  3. Students will explain why a daily work total varies even when a plan divides evenly.

Vocabulary

Water meter
A device that measures how much water a home or business uses so the utility can bill fairly. Reading the meter can also reveal hidden leaks.

Also: route, technician, remainder, reading

Teacher overview

Every house in the fictional town of Turnbull has a water meter that records how much water the household used, and a technician walks a route each month to read them. The town splits its streets into a north route and a south route, and the technician plans the month by figuring out how many houses fall on each working day. This problem set follows that planning from street counts to a daily target. The misconception to watch for is treating the remainder in problem 4 as a fraction of a house, when the leftover houses in problem 5 are whole houses that have to be added to one of the days.

Answer Key

  1. Answer: 368 houses.
    46 × 8. Splitting 46 into 40 + 6 gives 40 × 8 = 320 and 6 × 8 = 48, and 320 + 48 = 368 houses.

  2. Answer: 918 houses.
    34 × 27. Splitting 27 into 20 + 7 gives 34 × 20 = 680 and 34 × 7 = 238, and 680 + 238 = 918 houses.

  3. Answer: 1,286 houses.
    The two routes add to 368 + 918 = 1,286 houses.

  4. Answer: 183 houses.
    1,286 ÷ 7. Seven goes into 12 hundreds 1 hundred times, using 700 and leaving 586. Seven goes into 586 eighty-three times, using 581 and leaving 5. The plan is 183 houses a day.

  5. Answer: 5 houses.
    The division in problem 4 leaves a remainder of 5. Those 5 houses are whole houses, so the technician adds them to one of the days rather than splitting them.

  6. Answer: 549 minutes.
    183 × 3. Splitting 183 into 180 + 3 gives 180 × 3 = 540 and 3 × 3 = 9, and 540 + 9 = 549 minutes.

  7. Answer: 244 houses.
    1,464 ÷ 6. Six goes into 14 hundreds 2 hundreds times, using 1,200 and leaving 264. Six goes into 264 forty-four times with nothing left, so the helper reads 244 houses a day.

  8. Answer: 190 miles.
    38 × 5. Splitting 38 into 30 + 8 gives 30 × 5 = 150 and 8 × 5 = 40, and 150 + 40 = 190 miles.

  9. Answer: Some days include the 5 leftover houses, and a meter that is hard to reach or a house with a locked gate slows the route down.
    Accept any answer that names the remainder from problem 5 or a real interruption such as weather, a blocked meter, or a customer question.

Differentiation

Support

Give students an area model grid for problems 1 and 2 with the tens and ones already separated, so each multiplication becomes two smaller products and one sum. For problem 4, supply the multiples of 7 up to 7 × 9 on a reference strip.

Extension

Ask students to build a 6-day plan for the same 1,286 houses, compare the daily number with the 7-day plan, and write one sentence about which schedule they would choose and why.

ELL supports

Pre-teach "route," "meter," "technician," and "left over" using a simple street map with houses drawn in rows. Provide the sentence frame: The route has ___ streets with ___ houses on each street, so it has ___ houses in all.

Extensions

Have students count the doors along one hallway of the school, estimate how long it would take to check each one at 3 minutes apiece, and compare their estimate with a timed trial of five doors.